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4x^2-5x+3=2
We move all terms to the left:
4x^2-5x+3-(2)=0
We add all the numbers together, and all the variables
4x^2-5x+1=0
a = 4; b = -5; c = +1;
Δ = b2-4ac
Δ = -52-4·4·1
Δ = 9
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{9}=3$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-5)-3}{2*4}=\frac{2}{8} =1/4 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-5)+3}{2*4}=\frac{8}{8} =1 $
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